81 lines
3.9 KiB
Python
81 lines
3.9 KiB
Python
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# Parser für die NEO-Referenz, erzeugt eine YAML-Datei.
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# Copyright 2008 Martin Roppelt
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# E-Mail: m.p.roppelt@web.de
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# This file is part of the German NEO-Layout Version 2.
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# German NEO-Layout Version 2 is free software: you can redistribute it and/or modify it under the terms of the GNU General Public License as published by the Free Software Foundation, either version 3 of the License, or (at your option) any later version.
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# You should have received a copy of the GNU General Public License along with German NEO-Layout Version 2. If not, see <http://www.gnu.org/licenses/>.
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import io, yaml
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a = [[0, 2, 6], [1, 5, 7]]
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try:
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# s: Quelldatei (source) öffnen:
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s = io.open('../A-REFERENZ-A/neo20.txt', 'r', 2, 'utf8').readlines()
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# g: Wörterbuch-Datei (Gerüst) öffnen:
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g = yaml.load(open('ref.skel'))
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# Tastaturfelder parsen:
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# Erzeuge Liste für die Tastaturfelder:
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# d: Liste der kombinierten Tastaturfelder („Alle Ebenen“)
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# m: Liste der Mini-Tastaturfelder
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d = m = [[], []]
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# Durchlaufe Tastaturfelder („Alle Ebenen“):
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# f: Iterator Tastaturfeld (field)
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# q: Feld der Such-Schlüssel (query)
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q = ['Ha', 'Za']
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for f in range(2):
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# Bestimme Zeile l (line): Position des Schlüssels q[f] in der Quelldatei (Beginn des Tastaturfeldes)
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l = s.index(g[q[f]])
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# Durchlaufe die Tastaturreihen:
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# r: Iterator Tastaturreihe (row)
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for r in range(6):
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# Erzeuge Liste für Tastaturreihe:
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d[f].append([])
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# Erzeuge Liste für die zeilenweise Beschriftung der Tasten der Tastaturreihe:
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z = [[], []]
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# i: Iterator Tastenzeile (iterator)
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for i in range(2):
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z[i] = s[l + (r + 1) * 3 - 1 -i].split(u'│')[1:-1]
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# Wenn die Zeilen einer Tastenreihe nicht gleich viele Tasten enthalten, gebe eine Fehlermeldung aus und beende das Skript:
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if len(z[0]) != len(z[1]):
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print u'Die Zeilen der %s. Reihe im Feld »%s« enthalten unterschiedlich viele Tasten!' % (1 + r, f)
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quit()
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# Durchlaufe die Zeilen der Tastaturreihe:
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# k: Iterator Tasten (key)
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for k in range(len(z[0])):
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# Erzeuge Wörterbuch für Taste:
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d[f][r].append({})
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# Schreibe Vollbreite der Taste:
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d[f][r][k]['v'] = len(z[0][k])
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# Wenn die Breite der Taste 5 bzw 7 ist (Normale Taste),
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# schreibe die Zeichen der Ebenen der Taste:
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# schreibe die Beschriftung der Taste:
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if len(z[0][k]) == 5 + 2 * f:
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# i: Iterator Tastenzeile
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for i in range(2):
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# j: Iterator Ebene
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for j in range(3):
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# Erzeuge Wörterbuch für Ebene der Taste:
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d[f][r][k][1 + i * 3 + j] = {}
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if f:
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if z[i][k][0] == ' ' and z[i][k][-1] == ' ':
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d[f][r][k][1 + i * 3 + j]['i'] = z[i][k][j * 2 + 1]
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else:
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d[f][r][k][1 + i * 3 + j]['i'] = z[i][k][a[0][j]: a[1][j]]
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else:
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d[f][r][k][1 + i * 3 + j]['i'] = z[i][k][j * 2]
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# Kopiere das Zeichen der 1. Ebene in die Beschriftung der Taste:
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# d[f][r][k]['i'] = d[f][r][k][1]['i']
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else:
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d[f][r][k]['i'] = z[1][k] + z[0][k]
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yaml.dump(d, open('ref.parse', 'w'))
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except IOError:
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print "I/O-Fehler"
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except yaml.YAMLError, exc:
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if hasattr(exc, 'problem_mark'):
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mark = exc.problem_mark
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print "YAML-Parserfehler: (%s:%s)" % (mark.line+1, mark.column+1)
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